Calculation Errors
Mistake: Making calculation mistakes in hurry
Solution: Double-check calculations, especially in percentages
Practice 100+ Infosys aptitude questions with detailed solutions. Quantitative aptitude, logical reasoning, and verbal ability questions from previous year IRT exams. Download Infosys aptitude questions PDF for free.
This comprehensive collection contains 200+ Infosys aptitude questions from previous year IRT exams with detailed solutions. Master quantitative aptitude, logical reasoning, and verbal ability to excel in Infosys placement.
| Section | Questions | Marks | Time | Cutoff |
|---|---|---|---|---|
| Reasoning Ability | 15-18 | 25 | 25-30 min | ~60% |
| Quantitative Ability | 15-18 | 25 | 30-35 min | ~60% |
| Verbal Ability | 15-18 | 20 | 20-25 min | ~50% |
| Total | 45-54 | 70 | 75-90 min | - |
Q1: Profit Percentage
A shopkeeper sells an item at 20% profit. If he had bought it at 10% less and sold it for ₹40 less, he would have gained 25%. Find the cost price.
Solution:
Let CP = ₹100SP at 20% profit = ₹120New CP (10% less) = ₹90New SP = ₹120 - ₹40 = ₹80Profit = (80-90)/90 × 100 = -11.11% (loss)
Using formula: CP = (Difference in SP × 100) / (Difference in profit %)CP = (40 × 100) / (25 - 20) = ₹800Answer: ₹800
Q2: Consumption Reduction
The price of a product is increased by 25%. By what percentage should the consumption be reduced so that the expenditure remains the same?
Solution:
Let original price = ₹100, consumption = 100 unitsNew price = ₹125Original expenditure = 100 × 100 = ₹10,000New consumption = 10,000 / 125 = 80 unitsReduction = (100 - 80) / 100 × 100 = 20%Answer: 20%
Q3: Overall Profit/Loss
A man sells two articles for ₹4000 each, one at 20% profit and the other at 20% loss. Find his overall profit or loss percentage.
Solution:
For first article: CP₁ = 4000 / 1.20 = ₹3333.33For second article: CP₂ = 4000 / 0.80 = ₹5000Total CP = ₹8333.33Total SP = ₹8000Loss = (8333.33 - 8000) / 8333.33 × 100 = 4%Answer: 4% loss
Q4: Successive Discounts
A shopkeeper offers two successive discounts of 20% and 15%. What is the effective discount percentage?
Solution:
Let MP = ₹100After first discount: 100 - 20% = ₹80After second discount: 80 - 15% = ₹68Effective discount = (100 - 68) / 100 × 100 = 32%Answer: 32%
Q5: Combined Work
A can complete a work in 12 days, B in 15 days. They work together for 4 days, then A leaves. In how many days will B complete the remaining work?
Solution:
A's 1 day work = 1/12B's 1 day work = 1/15Together in 1 day = 1/12 + 1/15 = 9/60 = 3/20Work done in 4 days = 4 × 3/20 = 12/20 = 3/5Remaining work = 1 - 3/5 = 2/5B will complete in = (2/5) / (1/15) = 6 daysAnswer: 6 days
Q6: Men Leaving
15 men can complete a work in 20 days. After 5 days, 5 men leave. How many more days will it take to complete the work?
Solution:
Total work = 15 × 20 = 300 man-daysWork done in 5 days = 15 × 5 = 75 man-daysRemaining work = 300 - 75 = 225 man-daysRemaining men = 15 - 5 = 10Days required = 225 / 10 = 22.5 daysAnswer: 22.5 days
Q7: Efficiency
A is twice as efficient as B. If A can complete a work in 10 days, how long will it take if both work together?
Solution:
A's efficiency = 2 units/dayB's efficiency = 1 unit/dayTotal work = 2 × 10 = 20 unitsTogether efficiency = 2 + 1 = 3 units/dayTime = 20 / 3 = 6.67 daysAnswer: 6.67 days
Q8: Train & Platform
A train crosses a platform in 30 seconds and a man standing on the platform in 18 seconds. If the speed of the train is 60 km/hr, find the length of the platform.
Solution:
Speed = 60 km/hr = 60 × 5/18 = 50/3 m/sLength of train = 50/3 × 18 = 300 m
Let platform length = x m(300 + x) / (50/3) = 30300 + x = 500x = 200 mAnswer: 200 m
Q9: Relative Speed
Two trains of lengths 200m and 300m are moving in opposite directions at speeds of 50 km/hr and 40 km/hr. Find the time taken to cross each other.
Solution:
Relative speed = 50 + 40 = 90 km/hr = 90 × 5/18 = 25 m/sTotal distance = 200 + 300 = 500 mTime = 500 / 25 = 20 secondsAnswer: 20 seconds
Q10: Milk & Water
In a mixture of 60 liters, the ratio of milk and water is 2:1. How much water should be added to make the ratio 1:2?
Solution:
Current: Milk = 40L, Water = 20LLet x liters water be added40 / (20 + x) = 1/280 = 20 + xx = 60 litersAnswer: 60 liters
Q11: Doubling Time
A sum of money doubles itself in 5 years at simple interest. In how many years will it become 4 times?
Solution:
If money doubles in 5 years, rate = 100/5 = 20% p.a.To become 4 times, interest needed = 300%Time = 300/20 = 15 yearsAnswer: 15 years
Q12: Compound Interest
Find the compound interest on ₹10,000 for 2 years at 10% per annum, compounded annually.
Solution:
Amount = P(1 + r/100)ⁿ = 10000(1.1)² = ₹12,100CI = 12,100 - 10,000 = ₹2,100Answer: ₹2,100
Q13: Sales Growth
The following table shows the sales of a company over 5 years. Find the average annual growth rate.
| Year | Sales (in crores) |
|---|---|
| 2020 | 100 |
| 2021 | 120 |
| 2022 | 150 |
| 2023 | 180 |
| 2024 | 200 |
Solution:
Average growth rate = [(120-100)/100 + (150-120)/120 + (180-150)/150 + (200-180)/180] / 4 × 100= [20% + 25% + 20% + 11.11%] / 4 = 19.03%Answer: 19.03%
Q14: Average Age
The average age of a class of 30 students is 20 years. If the teacher’s age is included, the average becomes 21 years. Find the teacher’s age.
Solution:
Total age of 30 students = 30 × 20 = 600Total age including teacher = 31 × 21 = 651Teacher's age = 651 - 600 = 51 yearsAnswer: 51 years
Q15: Ratio Problems
The ratio of boys to girls in a class is 3:2. If 5 more girls join, the ratio becomes 3:4. Find the initial number of students.
Solution:
Let boys = 3x, girls = 2xAfter: 3x / (2x + 5) = 3/412x = 6x + 156x = 15x = 2.5Initial students = 3x + 2x = 5x = 12.5 (round to 13)Answer: 13 students
Q16: LCM and HCF
Find the LCM of 12, 18, and 24.
Solution:
12 = 2² × 318 = 2 × 3²24 = 2³ × 3LCM = 2³ × 3² = 8 × 9 = 72Answer: 72
Q17: Divisibility
What is the smallest number that must be added to 1056 to make it divisible by 23?
Solution:
1056 ÷ 23 = 45 remainder 21Number to add = 23 - 21 = 2Answer: 2
Q18: Remainder Theorem
Find the remainder when 2^31 is divided by 5.
Solution:
Pattern: 2¹ mod 5 = 2, 2² mod 5 = 4, 2³ mod 5 = 3, 2⁴ mod 5 = 1Cycle repeats every 4 powers31 ÷ 4 = 7 remainder 3Remainder = 2³ mod 5 = 3Answer: 3
Q19: Ratio Problems
The ratio of ages of A and B is 3:5. After 5 years, the ratio becomes 4:6. Find the present age of A.
Solution:
Let present ages be 3x and 5xAfter 5 years: (3x + 5) / (5x + 5) = 4/66(3x + 5) = 4(5x + 5)18x + 30 = 20x + 202x = 10x = 5A's age = 3x = 15 yearsAnswer: 15 years
Q20: Compound Ratio
If A:B = 2:3 and B:C = 4:5, find A:C.
Solution:
A:B = 2:3 = 8:12B:C = 4:5 = 12:15A:C = 8:15Answer: 8:15
Q21: Age Problems
The sum of ages of father and son is 50 years. Five years ago, the father was 5 times as old as the son. Find the present age of the son.
Solution:
Let son's age = x, father's age = 50 - x5 years ago: (50 - x - 5) = 5(x - 5)45 - x = 5x - 256x = 70x = 11.67 ≈ 12 yearsAnswer: 12 years
Q22: Age Difference
A is twice as old as B. 10 years ago, A was 4 times as old as B. Find the present age of A.
Solution:
Let B's age = x, A's age = 2x10 years ago: (2x - 10) = 4(x - 10)2x - 10 = 4x - 402x = 30x = 15A's age = 2x = 30 yearsAnswer: 30 years
Q23: Average Calculation
The average of 5 numbers is 20. If one number is removed, the average becomes 18. Find the removed number.
Solution:
Sum of 5 numbers = 5 × 20 = 100Sum of 4 numbers = 4 × 18 = 72Removed number = 100 - 72 = 28Answer: 28
Q24: Weighted Average
A student scored 60, 70, and 80 in three subjects. If the weights are 2, 3, and 5 respectively, find the weighted average.
Solution:
Weighted average = (60×2 + 70×3 + 80×5) / (2+3+5)= (120 + 210 + 400) / 10= 730 / 10 = 73Answer: 73
Q25: Permutations
In how many ways can 5 people be arranged in a row?
Solution:
Number of arrangements = 5! = 5 × 4 × 3 × 2 × 1 = 120Answer: 120 ways
Q26: Combinations
In how many ways can 3 students be selected from a group of 10 students?
Solution:
C(10,3) = 10! / (3! × 7!) = (10 × 9 × 8) / (3 × 2 × 1) = 120Answer: 120 ways
Q27: Percentage Increase
If the price of a commodity increases from ₹100 to ₹125, what is the percentage increase?
Solution:
Increase = 125 - 100 = ₹25Percentage increase = (25/100) × 100 = 25%Answer: 25%
Q28: Work Efficiency
A and B can complete a work in 20 days and 30 days respectively. If they work together, in how many days will they complete the work?
Solution:
A's 1 day work = 1/20B's 1 day work = 1/30Together in 1 day = 1/20 + 1/30 = 5/60 = 1/12Time = 12 daysAnswer: 12 days
Q29: Speed Calculation
A car covers 240 km in 4 hours. What is its average speed?
Solution:
Speed = Distance / Time = 240 / 4 = 60 km/hrAnswer: 60 km/hr
Q30: Simple Interest
Find the simple interest on ₹5000 for 3 years at 8% per annum.
Solution:
SI = (P × R × T) / 100 = (5000 × 8 × 3) / 100 = ₹1200Answer: ₹1200
Q31: Profit Calculation
A shopkeeper buys an article for ₹500 and sells it for ₹600. Find his profit percentage.
Solution:
Profit = 600 - 500 = ₹100Profit % = (100/500) × 100 = 20%Answer: 20%
Q32: Time Calculation
If a train travels at 60 km/hr, how long will it take to cover 180 km?
Solution:
Time = Distance / Speed = 180 / 60 = 3 hoursAnswer: 3 hours
Q33: Ratio Simplification
Simplify the ratio 24:36:48.
Solution:
HCF of 24, 36, 48 = 12Simplified ratio = 24/12 : 36/12 : 48/12 = 2:3:4Answer: 2:3:4
Q34: Mixture Problem
In what ratio should water be mixed with milk costing ₹20 per liter to get a mixture worth ₹15 per liter?
Solution:
Using alligation:Water (₹0) Milk (₹20) \ / \ / ₹15Ratio = (20-15):(15-0) = 5:15 = 1:3Answer: 1:3
Q35: Age Problem
The present age of father is 3 times the age of his son. After 5 years, the father’s age will be 2.5 times the son’s age. Find the present age of son.
Solution:
Let son's age = x, father's age = 3xAfter 5 years: (3x + 5) = 2.5(x + 5)3x + 5 = 2.5x + 12.50.5x = 7.5x = 15 yearsAnswer: 15 years
Q36: Permutation
In how many ways can 4 books be arranged on a shelf?
Solution:
Number of arrangements = 4! = 4 × 3 × 2 × 1 = 24Answer: 24 ways
Q37: Probability
What is the probability of getting a head when a coin is tossed?
Solution:
Total outcomes = 2 (Head, Tail)Favorable outcomes = 1 (Head)Probability = 1/2 = 0.5Answer: 0.5 or 1/2
Q38: Average
The average of 6 numbers is 25. If one number is 30, what is the average of the remaining 5 numbers?
Solution:
Sum of 6 numbers = 6 × 25 = 150Sum of remaining 5 = 150 - 30 = 120Average of 5 = 120 / 5 = 24Answer: 24
Q39: Compound Interest
Find the compound interest on ₹5000 for 2 years at 10% per annum, compounded annually.
Solution:
Amount = P(1 + r/100)ⁿ = 5000(1.1)² = ₹6050CI = 6050 - 5000 = ₹1050Answer: ₹1050
Q40: Profit & Loss
A man sells an article at a loss of 10%. If he had sold it for ₹45 more, he would have gained 5%. Find the cost price.
Solution:
Let CP = ₹100SP at 10% loss = ₹90SP at 5% gain = ₹105Difference = 105 - 90 = ₹15When difference is ₹15, CP = ₹100When difference is ₹45, CP = (100/15) × 45 = ₹300Answer: ₹300
Q41: Time & Work
A can do a work in 8 days and B can do the same work in 12 days. In how many days will they complete the work together?
Solution:
A's 1 day work = 1/8B's 1 day work = 1/12Together = 1/8 + 1/12 = 5/24Time = 24/5 = 4.8 daysAnswer: 4.8 days
Q42: Number System
Find the HCF of 24 and 36.
Solution:
24 = 2³ × 336 = 2² × 3²HCF = 2² × 3 = 4 × 3 = 12Answer: 12
Q43: Percentage
What is 25% of 200?
Solution:
25% of 200 = (25/100) × 200 = 50Answer: 50
Q44: Ratio
Divide ₹1200 in the ratio 2:3:5.
Solution:
Total parts = 2 + 3 + 5 = 10First part = (2/10) × 1200 = ₹240Second part = (3/10) × 1200 = ₹360Third part = (5/10) × 1200 = ₹600Answer: ₹240, ₹360, ₹600
Q45: Speed & Distance
A train 150m long passes a platform 200m long in 14 seconds. Find the speed of the train.
Solution:
Total distance = 150 + 200 = 350 mTime = 14 secondsSpeed = 350/14 = 25 m/s = 25 × 18/5 = 90 km/hrAnswer: 90 km/hr
Q46: Interest
At what rate of simple interest will ₹5000 amount to ₹6000 in 4 years?
Solution:
Interest = 6000 - 5000 = ₹1000Rate = (I × 100) / (P × T) = (1000 × 100) / (5000 × 4) = 5%Answer: 5% per annum
Q47: Compound Interest
Find the compound interest on ₹8000 for 3 years at 5% per annum, compounded annually.
Solution:
Amount = P(1 + r/100)ⁿ = 8000(1.05)³ = ₹9261CI = 9261 - 8000 = ₹1261Answer: ₹1261
Q48: Profit Percentage
A shopkeeper marks an item 30% above cost price and gives a discount of 10%. Find his profit percentage.
Solution:
Let CP = ₹100Marked price = 100 + 30% = ₹130Discount = 10% of 130 = ₹13Selling price = 130 - 13 = ₹117Profit = 117 - 100 = ₹17Profit % = (17/100) × 100 = 17%Answer: 17%
Q49: Work Problem
A, B, and C can complete a work in 10, 15, and 20 days respectively. If they work together, in how many days will they complete the work?
Solution:
A's 1 day work = 1/10B's 1 day work = 1/15C's 1 day work = 1/20Together = 1/10 + 1/15 + 1/20 = (6+4+3)/60 = 13/60Time = 60/13 = 4.62 daysAnswer: 4.62 days
Q50: Speed Problem
A person covers a certain distance at 40 km/hr and returns at 60 km/hr. Find the average speed.
Solution:
Average speed = 2ab/(a+b) = (2 × 40 × 60)/(40+60) = 4800/100 = 48 km/hrAnswer: 48 km/hr
Q51: Number Series
Find the next number in the series: 2, 6, 12, 20, 30, ?
Solution:
Pattern: n × (n+1) where n = 1, 2, 3, 4, 5...1×2=2, 2×3=6, 3×4=12, 4×5=20, 5×6=30Next: 6×7 = 42Answer: 42
Q52: Pattern Series
Find the missing number: 5, 11, 23, 47, 95, ?
Solution:
Pattern: Each number = previous × 2 + 15×2+1=11, 11×2+1=23, 23×2+1=47, 47×2+1=95Next: 95×2+1 = 191Answer: 191
Q53: Complex Series
Find the missing number: 3, 7, 15, 31, 63, ?
Solution:
Pattern: Each number = previous × 2 + 13×2+1=7, 7×2+1=15, 15×2+1=31, 31×2+1=63Next: 63×2+1 = 127Answer: 127
Q54: Letter Shifting
If “COMPUTER” is coded as “EQORWVGT”, how is “KEYBOARD” coded?
Solution:
Pattern: Each letter is shifted by +2 positionsC→E, O→Q, M→O, P→R, U→W, T→V, E→G, R→T
KEYBOARD: K→M, E→G, Y→A, B→D, O→Q, A→C, R→T, D→FAnswer: MGADQCTF
Q55: Simple Coding
In a certain code, “MONEY” is written as “NPOFZ”. How is “BANK” written in that code?
Solution:
Each letter is shifted by +1M→N, O→P, N→O, E→F, Y→Z
BANK: B→C, A→B, N→O, K→LAnswer: CBOL
Q56: Pattern Coding
If “PENCIL” is coded as “RGPENK”, how is “PAPER” coded?
Solution:
Pattern: Each letter shifted by +2P→R, E→G, N→P, C→E, I→K, L→N
PAPER: P→R, A→C, P→R, E→G, R→TAnswer: RCRGT
Q57: Family Relations
Pointing to a man, a woman said, “His mother is the only daughter of my mother.” How is the woman related to the man?
Solution:
"Only daughter of my mother" = the woman herself"His mother is the woman" = the woman is the man's motherAnswer: Mother
Q58: Sibling Relations
A is the son of B. C is the daughter of B. D is the brother of A. How is D related to C?
Solution:
A and C are siblings (both children of B)D is brother of ATherefore, D is also brother of CAnswer: Brother
Q59: Seating Arrangement
Five friends A, B, C, D, E are sitting in a row. A is not at either end. B is to the right of A. C is between A and D. Who is sitting at the rightmost position?
Solution:
Let positions be: 1, 2, 3, 4, 5 (left to right)A is not at end, so A is at 2, 3, or 4B is to right of AC is between A and D
If A at 2: B at 3/4/5, C between A and D → A(2), C(3), D(4), B(5), E(1)Answer: B
Q60: Direction Sense
A person walks 5 km North, then 3 km East, then 2 km South. How far is he from starting point?
Solution:
Net North = 5 - 2 = 3 kmNet East = 3 kmDistance = √(3² + 3²) = √18 = 3√2 kmAnswer: 3√2 km
Q61: Number Series
Find the next number: 1, 4, 9, 16, 25, ?
Solution:
Pattern: n² where n = 1, 2, 3, 4, 5...1²=1, 2²=4, 3²=9, 4²=16, 5²=25Next: 6² = 36Answer: 36
Q62: Coding Pattern
If “APPLE” is coded as “BQQMF”, how is “ORANGE” coded?
Solution:
Pattern: Each letter shifted by +1A→B, P→Q, P→Q, L→M, E→FORANGE: O→P, R→S, A→B, N→O, G→H, E→FAnswer: PSBOHF
Q63: Blood Relations
Pointing to a photograph, a man said, “She is the daughter of my father’s only son.” How is the woman related to the man?
Solution:
"My father's only son" = the man himself"She is the daughter of the man" = the woman is the man's daughterAnswer: Daughter
Q64: Series Pattern
Find the missing number: 2, 5, 10, 17, 26, ?
Solution:
Pattern: n² + 1 where n = 1, 2, 3, 4, 5...1²+1=2, 2²+1=5, 3²+1=10, 4²+1=17, 5²+1=26Next: 6²+1 = 37Answer: 37
Q65: Logical Deduction
Statements: All birds can fly. Penguins are birds.
Conclusion: Penguins can fly.
Is the conclusion valid?
Solution:
The first statement is false (not all birds can fly).Penguins are birds but cannot fly.Conclusion is invalid.Answer: Invalid (first premise is false)
Q66: Direction Problem
A person walks 6 km East, then 8 km North. How far is he from the starting point?
Solution:
Distance = √(6² + 8²) = √(36 + 64) = √100 = 10 kmAnswer: 10 km
Q67: Series
Find the next number: 1, 3, 6, 10, 15, ?
Solution:
Pattern: n(n+1)/2 where n = 1, 2, 3, 4, 5...1×2/2=1, 2×3/2=3, 3×4/2=6, 4×5/2=10, 5×6/2=15Next: 6×7/2 = 21Answer: 21
Q68: Coding
If “CAT” is coded as “3120”, how is “DOG” coded? (A=1, B=2, C=3…)
Solution:
C=3, A=1, T=20 → 3120D=4, O=15, G=7 → 4157Answer: 4157
Q69: Series
Find the missing number: 8, 12, 18, 26, 36, ?
Solution:
Pattern: Differences are 4, 6, 8, 10...Next difference = 12Missing number = 36 + 12 = 48Answer: 48
Q70: Logical Reasoning
If all roses are flowers and some flowers are red, which statement is definitely true?
Options: A) All roses are red B) Some roses are red C) Some red things are flowers D) All flowers are roses
Answer: C) Some red things are flowers
Q71: Series
Find the next number: 64, 32, 16, 8, 4, ?
Solution:
Pattern: Each number is half of previous64/2=32, 32/2=16, 16/2=8, 8/2=4Next: 4/2 = 2Answer: 2
Q72: Coding
If “MAN” is coded as “13114”, how is “WOMAN” coded? (A=1, B=2…)
Solution:
M=13, A=1, N=14 → 13114W=23, O=15, M=13, A=1, N=14 → 231513114Answer: 231513114
Q73: Blood Relations
A is the father of B. B is the brother of C. How is A related to C?
Solution:
A is father of BB is brother of CTherefore, A is also father of CAnswer: Father
Q74: Series Pattern
Find the next number: 1, 8, 27, 64, 125, ?
Solution:
Pattern: n³ where n = 1, 2, 3, 4, 5...1³=1, 2³=8, 3³=27, 4³=64, 5³=125Next: 6³ = 216Answer: 216
Q75: Logical Reasoning
Statements: Some cats are dogs. All dogs are animals.
Conclusion: Some cats are animals.
Is the conclusion valid?
Solution:
Some cats are dogs, and all dogs are animals.Therefore, some cats are animals.Conclusion is valid.Answer: Valid
Q76: Technology Passage
Passage: Artificial Intelligence (AI) has revolutionized various industries, from healthcare to finance. Machine learning algorithms can now diagnose diseases with higher accuracy than human doctors in some cases. However, concerns about job displacement and ethical implications remain.
Questions:
Answers:
Q77: Error Spotting
Identify the error in: “Neither of the students were present in the class.”
Solution:
Error: Subject-verb agreement"Neither" is singular, so verb should be "was"Correct: "Neither of the students was present in the class."Q78: Sentence Correction
Correct: “The data is incorrect.”
Solution:
"Data" is plural, so verb should be "are"Correct: "The data are incorrect."Q79: Synonyms
Find synonym of “Abundant”
Options: A) Scarce B) Plentiful C) Rare D) Limited
Answer: B) Plentiful
Q80: Antonyms
Find antonym of “Benevolent”
Options: A) Kind B) Generous C) Malevolent D) Charitable
Answer: C) Malevolent
Q81: Sentence Rearrangement
Arrange in logical order:
Solution:
Logical order: 2, 1, 3, 4- Starting a business can be rewarding- However, it requires careful planning- Market research is essential- Success depends on multiple factorsQ82: Fill in the Blanks
The company’s profits have been _____ steadily over the past year.
Options: A) declining B) decliningly C) decline D) declined
Answer: A) declining
Q83: Sentence Completion
The manager was _____ with the team’s performance and decided to reward them.
Options: A) pleased B) pleasing C) please D) pleases
Answer: A) pleased
Q84: Antonyms
Find antonym of “Temporary”
Options: A) Brief B) Permanent C) Short D) Momentary
Answer: B) Permanent
Q85: Synonyms
Find synonym of “Enormous”
Options: A) Tiny B) Huge C) Small D) Little
Answer: B) Huge
Q86: Grammar - Prepositions
Choose the correct preposition: The meeting will be held _____ 3 PM.
Options: A) at B) on C) in D) by
Answer: A) at
Q87: Vocabulary - Context
The new policy will _____ significant changes in the organization.
Options: A) effect B) affect C) impact D) influence
Answer: B) affect
Q88: Grammar
Choose the correct form: “Neither the teacher nor the students _____ present.”
Options: A) was B) were C) is D) are
Answer: B) were
Q89: Grammar
Choose the correct form: “The number of students _____ increased.”
Options: A) have B) has C) are D) were
Answer: B) has
Q90: Error Spotting
Identify the error: “Each of the students have submitted their assignments.”
Solution:
Error: Subject-verb agreement"Each" is singular, so verb should be "has"Correct: "Each of the students has submitted his/her assignment."Answer: Subject-verb agreement error
Q91: Error Spotting
Identify the error: “The team of players are ready.”
Solution:
Error: "Team" is a collective noun, should use singular verbCorrect: "The team of players is ready."Answer: Subject-verb agreement error
Q92: Error Spotting
Identify the error: “The data shows that the results are positive.”
Solution:
"Data" is plural, so verb should be "show"Correct: "The data show that the results are positive."Answer: Subject-verb agreement error
Q93: Vocabulary
Find synonym of “Courageous”
Options: A) Fearful B) Brave C) Timid D) Cowardly
Answer: B) Brave
Q94: Vocabulary
Find antonym of “Generous”
Options: A) Kind B) Stingy C) Giving D) Charitable
Answer: B) Stingy
Q95: Percentage
If 20% of a number is 40, what is the number?
Solution:
20% of number = 40Number = (40/20) × 100 = 200Answer: 200
Q96: Ratio
If A:B = 3:4 and B:C = 5:6, find A:B:C.
Solution:
A:B = 3:4 = 15:20B:C = 5:6 = 20:24A:B:C = 15:20:24Answer: 15:20:24
| Topic | Questions | Weightage |
|---|---|---|
| Percentages & Profit Loss | 20-25 | High |
| Time & Work | 15-20 | High |
| Time, Speed & Distance | 10-15 | Medium |
| Number System | 10-15 | Medium |
| Data Interpretation | 8-12 | Medium |
| Series & Sequences | 15-20 | High |
| Coding-Decoding | 10-15 | Medium |
| Blood Relations | 8-12 | Medium |
| Puzzles | 10-15 | Medium |
| Reading Comprehension | 12-18 | High |
| Grammar | 15-20 | High |
| Vocabulary | 10-15 | Medium |
Calculation Errors
Mistake: Making calculation mistakes in hurry
Solution: Double-check calculations, especially in percentages
Time Management
Mistake: Spending too much time on difficult questions
Solution: Set time limits (1-2 min per question), move on if stuck
Formula Application
Mistake: Applying wrong formulas
Solution: Understand concepts, memorize key formulas
Reading Comprehension
Mistake: Not reading passage carefully
Solution: Read passage twice, understand context before answering
Ready to master Infosys aptitude? Practice these 200+ questions regularly, focus on time management, and ensure you clear sectional cutoffs (60% in Reasoning & Quantitative, 50% in Verbal). Download Infosys placement papers for more practice!
Pro Tip: Solve at least 15-20 previous year Infosys IRT papers before your actual exam. Focus on percentages, time & work, and series as they are most frequently asked.