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Download Microsoft placement papers 2024 PDF with previous year online assessment questions, solutions, and exam pattern analysis for 2024 recruitment cycle.
This page contains Microsoft placement papers from 2024 with previous year online assessment questions, solutions, and exam patterns. Use these papers to understand the 2024 Microsoft OA pattern and practice with actual questions.
| Section | Questions | Time | Difficulty | Focus Areas |
|---|---|---|---|---|
| Coding Problem 1 | 1 | 20 min | Medium | Arrays, strings |
| Coding Problem 2 | 1 | 20 min | Medium | Trees, graphs |
| Coding Problem 3 | 1 | 25 min | Hard | Dynamic programming |
| Coding Problem 4 | 1 | 25 min | Hard | Advanced DSA |
Total: 3-4 problems, 60-90 minutes
Platform: Microsoft Codility or HackerRank
Languages Allowed: C++, Java, Python, C#
Success Rate: ~15-20% cleared OA and advanced to interviews
This section contains real coding questions from Microsoft OA 2024 based on candidate experiences from LeetCode, GeeksforGeeks, and interview forums.
Example:
Input: nums = [2,7,11,15], target = 9Output: [0,1]Solution (C++):
vector<int> twoSum(vector<int>& nums, int target) { unordered_map<int, int> map; for (int i = 0; i < nums.size(); i++) { int complement = target - nums[i]; if (map.find(complement) != map.end()) { return {map[complement], i}; } map[nums[i]] = i; } return {};}Time Complexity: O(n)
Space Complexity: O(n)
Example:
Tree: 1 / \ 2 3Output: 6 (path: 2->1->3)Solution (C++):
int maxPathSum(TreeNode* root) { int maxSum = INT_MIN; maxPathSumHelper(root, maxSum); return maxSum;}
int maxPathSumHelper(TreeNode* node, int& maxSum) { if (!node) return 0;
int left = max(0, maxPathSumHelper(node->left, maxSum)); int right = max(0, maxPathSumHelper(node->right, maxSum));
maxSum = max(maxSum, node->val + left + right);
return node->val + max(left, right);}Time Complexity: O(n)
Space Complexity: O(h) where h is height
Example:
Input: nums = [10,9,2,5,3,7,101,18]Output: 4Solution (C++):
int lengthOfLIS(vector<int>& nums) { vector<int> dp(nums.size(), 1); int maxLen = 1;
for (int i = 1; i < nums.size(); i++) { for (int j = 0; j < i; j++) { if (nums[j] < nums[i]) { dp[i] = max(dp[i], dp[j] + 1); } } maxLen = max(maxLen, dp[i]); }
return maxLen;}Time Complexity: O(n²)
Space Complexity: O(n)
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Based on candidate experiences from 2024 Microsoft interviews:
2024 Interview Process:
Common 2024 Interview Topics:
2024 Interview Questions Examples:
Success Tips:
Difficulty Rating: 3.1/5
For detailed interview experiences, visit Microsoft Interview Experience page.
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Practice 2024 papers to understand Microsoft OA pattern!